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Grade 7 · Grade 7 / Pre-algebra · 8 minute lesson

Work backward from a discounted amount

A discounted price is a fraction of the original, so reverse percentages require division by the remaining fraction.

Lesson 6 of 30 in Grade 7. Take the time you need; the lesson estimate is a guide.

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01 · Read and understand

What you will learn

  • Explain how to work backward from a discounted amount.
  • Solve the two practice problems and explain how the assumptions affect the answers.

Before you start

Percent multipliers and one-step equations.

Keep paper nearby. Read the question once for the context, then again to identify what is known and what you need to find.

Start with a question

A fictional art kit costs $42 after a 30% discount. What was the price before the discount?

Why this math matters

A discounted price is a fraction of the original, so reverse percentages require division by the remaining fraction. Use a multiplier equation to recover original dimensions, populations, or prices from a percentage change.

A collection of concrete mathematics tools for building mathematical understanding
Make a representation of your own.Sketch the quantities or relationships in this question before working through the solution. The cover image sets the learning scene; it does not show this problem’s exact values.

Set up the model

A useful answer starts with clear assumptions:

  • The discount applies once to the original price.
  • There are no other charges in this example.

02 · Work through the example

Follow the reasoning, one step at a time.

Try to predict the next step before reading it. After each calculation, explain why the operation makes sense and how it helps answer the original question.

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The complete worked example, one idea at a time.

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Work backward from a discounted amount

Paused

Question: Start with the question. Paused.

Question

Start with the question

A fictional art kit costs $42 after a 30% discount. What was the price before the discount?

Before you calculate

Read what is known and what you need to find. Make a prediction before moving to the first calculation.

Starts paused. Play advances through the full text at a reading pace; pause whenever you need more time. Previous, Next, and the phase buttons let you set your own pace. Playback pauses when this walkthrough leaves the screen or you switch tabs.

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  1. Represent the quantities

    remaining fraction = 1 − 0.30 = 0.70

    A 30% discount leaves 70% of the original amount.

  2. Apply the relationship

    0.70p = 42; p = 42/0.70

    Divide the known final amount by the retained fraction.

  3. Check and interpret

    p = $60; 60 − 0.30(60) = $42

    The forward calculation confirms the recovered original price.

The result

p = $60; 60 − 0.30(60) = $42

The forward calculation confirms the recovered original price.

Common mistakes to catch

  • Adding 30% of the discounted price uses the wrong base.
  • A decrease of 30% uses a multiplier of 0.70, not 0.30.

03 · Practice independently

Try it before revealing the answer.

Use paper or a calculator as needed. Write your units and reasoning, then open the hint or explanation to check your approach.

Practice 1

A quantity is 72 after a 20% decrease. Find its original value.

Show a hint

The final amount is 80% of the original.

Reveal answer and explanation

90

72/0.80 = 90.

Practice 2

A quantity is 96 after a 20% increase. Find its original value.

Show a hint

An increase retains 120%, not 80%.

Reveal answer and explanation

80

96/1.20 = 80, and 80 + 16 = 96.

Take the idea with you

Use a multiplier equation to recover original dimensions, populations, or prices from a percentage change.

04 · Reflect and continue

Can you explain it in your own words?

Before moving on, explain the main idea without looking at the worked example. Try both practice questions, check your reasoning, and name one mistake you now know how to avoid. Return to a step if you still need support.

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Up next: Match time units in simple interest

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