Grade 11 · Exponential calibration
Exponential calibration: Slow decay from one
Exponential calibration: investigate slow decay from one with initial value a = 1; exponential rate b = -0.1.
Predict what will happen, press Play, then pause and explain what changed. Every control also works without playback.
Watch the relationship
PausedHD animation studio
From experiment to screen.
Present a crisp Canvas scene, save a full-HD image, or capture your model as a silent video.
Understand what you are seeing
The idea behind the motion.
The initial amount and proportional growth rate play different roles. Multiplying a scales every output, but changing b changes each time interval's multiplicative factor. A negative rate produces decay without making a positive starting amount negative. This investigation starts with Initial value a = 1; Exponential rate b = -0.1. Predict the result before playing, then change one parameter while keeping the other fixed to test the reason for the change.
A relationship to keep
f(t)=a e^(bt); f′(t)=b f(t)
Read the symbols alongside the explanation. A diagram shows the relationship; the assumptions tell you when it applies.
- STEP 1
Set up the mathematical model
Read the initial value at t=0 and predict whether the rate produces growth, decay, or a constant curve. The starting case is “Slow decay from one.”
- STEP 2
Follow the changing quantity
Trace four time units. Compare the changing amount with its instantaneous rate b times the amount.
- STEP 3
Explain and test the result
Divide the ending amount by the starting amount to recover e^(bt). Compare equal time intervals rather than equal changes in height.
Your turn to explain
Make a prediction. Test your reasoning.
Keep Initial value a = 1; Exponential rate b = -0.1. Pause the timeline at 60%. Given time / input = 2.4, calculate current amount, instantaneous rate, growth multiplier. Show the substitution into the displayed formula.
Use the values specified in the question. Reset restores the initial values for this investigation.
Compare your explanation
Substitution gives y=1 exp((-0.1)(2.4))=0.786628. The rate is k y=(-0.1)(0.786628)=-0.078663, rather than just the amount y. Results: Current amount: 0.787; Instantaneous rate: -0.079; Growth multiplier: 0.787. Decimal values are rounded; retain the original parameters when checking.
Work through a full lesson
Connect the animation to a worked example and practice questions.