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Grade 9 · Intermediate · 12 minute lesson

Clear fractions in a linear inequality

Multiply by a positive common denominator before solving a linear inequality.

Lesson 9 of 30 in Grade 9. Take the time you need; the lesson estimate is a guide.

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01 · Read and understand

What you will learn

  • Multiply by a positive common denominator before solving a linear inequality.
  • Justify the method and check its domain, units, or logical conditions.

Before you start

Signed arithmetic, fraction and decimal operations, one-step equations, and introductory coordinate graphs.

Keep paper nearby. Read the question once for the context, then again to identify what is known and what you need to find.

Start with a question

Solve 2(x−3)/3 ≤ (x+4)/2 over the real numbers.

Why this math matters

Clear fixed fractional coefficients while preserving the direction and domain of an inequality. The example connects a stated condition to a conclusion and then checks whether the result satisfies that condition.

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Make a representation of your own.Sketch the quantities or relationships in this question before working through the solution. The cover image sets the learning scene; it does not show this problem’s exact values.

Set up the model

A useful answer starts with clear assumptions:

  • Use the real-number system and the restrictions or data model stated in the question unless another domain is specified.
  • Treat provided measurements as exact classroom-model values unless an approximation or uncertainty is stated.

02 · Work through the example

Follow the reasoning, one step at a time.

Try to predict the next step before reading it. After each calculation, explain why the operation makes sense and how it helps answer the original question.

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See this example unfold.

The complete worked example, one idea at a time.

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Clear fractions in a linear inequality

Paused

Question: Start with the question. Paused.

Question

Start with the question

Solve 2(x−3)/3 ≤ (x+4)/2 over the real numbers.

Before you calculate

Read what is known and what you need to find. Make a prediction before moving to the first calculation.

Starts paused. Play advances through the full text at a reading pace; pause whenever you need more time. Previous, Next, and the phase buttons let you set your own pace. Playback pauses when this walkthrough leaves the screen or you switch tabs.

Your device’s reduced-motion setting keeps each phase still. Manual controls remain available. The full written solution stays below.

  1. Represent the conditions

    Multiply both sides by 6: 4(x−3) ≤ 3(x+4)

    The positive common denominator clears both fractions without reversing the inequality.

  2. Develop the calculation

    4x−12 ≤ 3x+12

    Distribute both multipliers before collecting terms.

  3. Check and interpret

    x ≤ 24

    Subtract 3x and add 12; at x=24 both original sides equal fourteen, so the boundary is included.

The result

x ≤ 24

Subtract 3x and add 12; at x=24 both original sides equal fourteen, so the boundary is included.

Common mistakes to catch

  • Multiply every term on both sides by the common denominator.
  • Do not use this shortcut with a variable denominator before checking its sign and excluded inputs.

03 · Practice independently

Try it before revealing the answer.

Use paper or a calculator as needed. Write your units and reasoning, then open the hint or explanation to check your approach.

Practice 1

Solve (x−2)/3 > (x+1)/4.

Show a hint

Multiply both sides by positive twelve.

Reveal answer and explanation

x > 11

4x−8 > 3x+3 gives x>11; equality at eleven is excluded.

Practice 2

Why can a positive common denominator be used without reversing the inequality here?

Show a hint

The denominators two and three are fixed positive numbers.

Reveal answer and explanation

The multiplier six is positive for every allowed input

A variable denominator could change sign or be zero, so its sign and domain would need separate analysis before multiplication.

Take the idea with you

Clear fixed fractional coefficients while preserving the direction and domain of an inequality.

04 · Reflect and continue

Can you explain it in your own words?

Before moving on, explain the main idea without looking at the worked example. Try both practice questions, check your reasoning, and name one mistake you now know how to avoid. Return to a step if you still need support.

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Up next: Solve a two-sided bound

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