Graduate · Rare events and convergence
Rare events and convergence: A near-balanced decaying mean
Rare events and convergence: investigate a near-balanced decaying mean with magnitude exponent a = 1.25; rarity exponent b = 1.5.
Predict what will happen, press Play, then pause and explain what changed. Every control also works without playback.
Watch the relationship
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Understand what you are seeing
The idea behind the motion.
An event can become rare while its size increases. The nonzero probability tends to zero whenever b>0, giving convergence in probability to zero, but the mean absolute value depends on the competition between a and b. The same family can therefore converge in L¹, fail with a constant mean, or have a growing mean. This investigation starts with Magnitude exponent a = 1.25; Rarity exponent b = 1.5. Predict the result before playing, then change one parameter while keeping the other fixed to test the reason for the change.
A relationship to keep
Xₙ=nᵃ with probability n⁻ᵇ, else 0; E|Xₙ|=n^(a−b)
Read the symbols alongside the explanation. A diagram shows the relationship; the assumptions tell you when it applies.
- STEP 1
Set up the mathematical model
Separate the nonzero value nᵃ from the probability n⁻ᵇ attached to it. The starting case is “A near-balanced decaying mean.”
- STEP 2
Follow the changing quantity
Increase n from one to thirty and compare their product with each factor separately.
- STEP 3
Explain and test the result
Classify the asymptotic mean by the sign of a−b. For b>1, the probabilities have a finite sum, so the first Borel–Cantelli lemma gives eventual zero almost surely for any joint construction on one probability space. For 0<b≤1, the dependence between events matters.
Your turn to explain
Make a prediction. Test your reasoning.
Keep Magnitude exponent a = 1.25; Rarity exponent b = 1.5. Pause the timeline at 40%. Given index n = 12, calculate nonzero probability, nonzero magnitude, mean absolute value. Show the substitution into the displayed formula.
Use the values specified in the question. Reset restores the initial values for this investigation.
Compare your explanation
At n=12, probability is (12)^(−1.5)=0.024056 and magnitude is (12)^1.25=22.334517. Their product is n^(a−b)=(12)^(1.25−1.5)=0.537285. Results: Nonzero probability: 0.024; Nonzero magnitude: 22.335; Mean absolute value: 0.537. Decimal values are rounded; retain the original parameters when checking.
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