Grade 12 · Signed accumulation
Signed accumulation: A shallow negative beginning
Signed accumulation: investigate a shallow negative beginning with slope a = 0.5; subtracted intercept b = 0.5.
Predict what will happen, press Play, then pause and explain what changed. Every control also works without playback.
Watch the relationship
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The idea behind the motion.
A definite integral adds signed contributions: portions below the axis subtract, while portions above it add. Total geometric area instead adds both magnitudes. A moving upper bound makes the difference visible before, at, and after the line crosses the axis. This investigation starts with Slope a = 0.5; Subtracted intercept b = 0.5. Predict the result before playing, then change one parameter while keeping the other fixed to test the reason for the change.
A relationship to keep
∫₀ᵀ(ax−b)dx=aT²/2−bT
Read the symbols alongside the explanation. A diagram shows the relationship; the assumptions tell you when it applies.
- STEP 1
Set up the mathematical model
Locate the zero crossing b/a and predict the sign of the integrand on each side. The starting case is “A shallow negative beginning.”
- STEP 2
Follow the changing quantity
Expand the shaded interval from zero to four. Compare the current integral with the total geometric area.
- STEP 3
Explain and test the result
Find a case where positive and negative contributions cancel. A zero net integral can coexist with a strictly positive geometric area.
Your turn to explain
Make a prediction. Test your reasoning.
Keep Slope a = 0.5; Subtracted intercept b = 0.5. Pause the timeline at 40%. Given upper bound = 1.6, calculate signed integral, total geometric area, zero crossing. Show the substitution into the displayed formula.
Use the values specified in the question. Reset restores the initial values for this investigation.
Compare your explanation
The signed integral is (0.5)(1.6)²/2−(0.5)(1.6)=-0.16. The negative triangle has area b²/(2a)=0.25; reversing its sign adds twice that amount, giving 0.34. Results: Signed integral: -0.16; Total geometric area: 0.34; Zero crossing: 1. Decimal values are rounded; retain the original parameters when checking.
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