Grade 12 · Cubic derivatives
Cubic derivatives: Negative cubic with negative drift
Cubic derivatives: investigate negative cubic with negative drift with cubic coefficient a = -0.5; linear coefficient b = -2.
Predict what will happen, press Play, then pause and explain what changed. Every control also works without playback.
Watch the relationship
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Understand what you are seeing
The idea behind the motion.
A cubic's height, slope, and change of slope answer different questions. The moving tangent shows why a point with zero height need not have zero slope. Varying the linear term can add or remove stationary points while the second derivative still changes sign at zero when a is nonzero. This investigation starts with Cubic coefficient a = -0.5; Linear coefficient b = -2. Predict the result before playing, then change one parameter while keeping the other fixed to test the reason for the change.
A relationship to keep
f(x)=ax³+bx; f′=3ax²+b; f″=6ax
Read the symbols alongside the explanation. A diagram shows the relationship; the assumptions tell you when it applies.
- STEP 1
Set up the mathematical model
Predict the function value at zero and separately calculate its first derivative there. The starting case is “Negative cubic with negative drift.”
- STEP 2
Follow the changing quantity
Trace from x=−2 to x=2 while comparing the tangent's direction with the derivative readout.
- STEP 3
Explain and test the result
Use both derivatives to distinguish a stationary inflection from an ordinary crossing. If a=0, identify the resulting linear function.
Your turn to explain
Make a prediction. Test your reasoning.
Keep Cubic coefficient a = -0.5; Linear coefficient b = -2. Pause the timeline at 100%. Given input x = 2, calculate function value, first derivative, second derivative. Show the substitution into the displayed formula.
Use the values specified in the question. Reset restores the initial values for this investigation.
Compare your explanation
At x=2, f=(-0.5)(2)³+(-2)(2)=-8. Differentiation gives f′=3(-0.5)(2)²+(-2)=-8 and f″=6(-0.5)(2)=-6. Results: Function value: -8; First derivative: -8; Second derivative: -6. Decimal values are rounded; retain the original parameters when checking.
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