Math With AmarA C A D E M Y

Undergraduate · Directional derivatives · 28 of 650

Directional derivatives · x² coefficient a=2.5; y² coefficient b=2.5

Set θ=6π/5 radians. Find the directional derivative and the largest possible unit-direction derivative at this point. Givens: x² coefficient a=2.5; y² coefficient b=2.5.

Try the question, use a hint when you need one, and compare your reasoning with the worked solution. The animation starts with this chapter’s values; changing its controls explores a new case.

01 · Make a prediction

Your practice question

Let f(x,y)=2.5x²+2.5y², evaluated at the fixed point (1,1). Use a unit direction u=(cos θ,sin θ). Set θ=6π/5 radians. Find the directional derivative and the largest possible unit-direction derivative at this point.

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02 · Explore the model

See the mathematical relationship move.

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Watch the relationship

Paused
Directional derivatives · x² coefficient a=2.5; y² coefficient b=2.5. Direction radians: 0. Directional derivative: 5. Maximum unit-direction rate: 7.071A unit direction samples the gradient-7.077.0703.146.28directional derivativedirection angle (radians) → · labeled axes rescale to this model
The point is fixed at (1,1); only direction varies during playback. The quadratic coefficients are positive. A zero directional derivative is a local first-order statement and does not make the function constant along that whole line.

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Make it your experiment

Change one value. Notice what follows.

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Direction radians
0
Directional derivative
5
Maximum unit-direction rate
7.071

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From experiment to screen.

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The mathematical idea

The directional derivative is a dot product with a unit direction, so it depends on orientation as well as gradient length. Rotating a unit vector through all angles reveals a maximum equal to the gradient norm and a minimum equal to its negative. Perpendicular directions have zero first-order change. Let f(x,y)=2.5x²+2.5y², evaluated at the fixed point (1,1). Use a unit direction u=(cos θ,sin θ). Set θ=6π/5 radians. The requested state occurs at 60% playback; use the exact target stated in the question for your calculation.

f=ax²+by²; ∇f(1,1)=(2a,2b); Dᵤf=∇f·u

03 · Reflect and transfer

Explain what changes and why.

What changes if the direction vector has length two rather than one, and why must direction vectors be normalized here?

This is a distinct guided scenario using a reusable mathematical model. Similar-looking diagrams can represent different given values and conclusions; they are not different mathematical theories.