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Grade 12 · Advanced · 15 minute lesson

Change integral limits along with the variable

Use a substitution consistently in a definite integral.

Lesson 25 of 30 in Grade 12. Take the time you need; the lesson estimate is a guide.

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01 · Read and understand

What you will learn

  • Use a substitution consistently in a definite integral.
  • Justify the conclusion "The integral is ∫₀¹exp(u)du=e−1" using the stated assumptions.

Before you start

Chain rule and elementary antiderivatives.

Keep paper nearby. Read the question once for the context, then again to identify what is known and what you need to find.

Start with a question

Evaluate ∫₀¹2x exp(x²) dx.

Why this math matters

Use a substitution consistently in a definite integral. This worked micro-lesson connects a precise mathematical condition to a conclusion you can check. The transfer task asks you to change the setting and decide which parts of the reasoning still apply.

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Make a representation of your own.Sketch the quantities or relationships in this question before working through the solution. The cover image sets the learning scene; it does not show this problem’s exact values.

Set up the model

A useful answer starts with clear assumptions:

  • The substitution is smooth and monotone on the intervals used.
  • exp denotes the natural exponential.

02 · Work through the example

Follow the reasoning, one step at a time.

Try to predict the next step before reading it. After each calculation, explain why the operation makes sense and how it helps answer the original question.

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Work through it with Amar

See this example unfold.

The complete worked example, one idea at a time.

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Change integral limits along with the variable

Paused

Question: Start with the question. Paused.

Question

Start with the question

Evaluate ∫₀¹2x exp(x²) dx.

Before you calculate

Read what is known and what you need to find. Make a prediction before moving to the first calculation.

Starts paused. Play advances through the full text at a reading pace; pause whenever you need more time. Previous, Next, and the phase buttons let you set your own pace. Playback pauses when this walkthrough leaves the screen or you switch tabs.

Your device’s reduced-motion setting keeps each phase still. Manual controls remain available. The full written solution stays below.

  1. Build the model

    Set u=x², so du=2x dx

    The derivative of the inner expression matches the remaining factor.

  2. Work through the mathematics

    x=0 gives u=0 and x=1 gives u=1

    The bounds are translated into the new variable.

  3. Check the conclusion

    The integral is ∫₀¹exp(u)du=e−1

    The antiderivative is evaluated entirely in the substituted variable.

The result

The integral is ∫₀¹exp(u)du=e−1

The antiderivative is evaluated entirely in the substituted variable.

Common mistakes to catch

  • Do not mix original bounds with the substituted variable.
  • Match the inner derivative before choosing a substitution.

03 · Practice independently

Try it before revealing the answer.

Use paper or a calculator as needed. Write your units and reasoning, then open the hint or explanation to check your approach.

Practice 1

Evaluate ∫₁²2x exp(x²) dx.

Show a hint

Convert the bounds to one and four.

Reveal answer and explanation

e⁴−e

The new upper bound is four, not two.

Practice 2

Why is replacing x² by u alone insufficient?

Show a hint

The differential changes too.

Reveal answer and explanation

The factor 2x dx must become du

A valid change of variables transforms both the integrand and the integration measure.

Take the idea with you

Reverse a chain-rule pattern to simplify an accumulated quantity.

04 · Reflect and continue

Can you explain it in your own words?

Before moving on, explain the main idea without looking at the worked example. Try both practice questions, check your reasoning, and name one mistake you now know how to avoid. Return to a step if you still need support.

Next lesson

Up next: Reverse the product rule to integrate a product

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