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Grade 12 · Advanced · 15 minute lesson

Differentiate when the base and exponent both vary

Use a logarithm to turn a variable power into a product.

Lesson 19 of 30 in Grade 12. Take the time you need; the lesson estimate is a guide.

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Grade 12 chapters and video availability

01 · Read and understand

What you will learn

  • Use a logarithm to turn a variable power into a product.
  • Justify the conclusion "y′=xˣ(ln x+1)" using the stated assumptions.

Before you start

Logarithms, product rule, and chain rule.

Keep paper nearby. Read the question once for the context, then again to identify what is known and what you need to find.

Start with a question

Differentiate y=xˣ for x>0.

Why this math matters

Use a logarithm to turn a variable power into a product. This worked micro-lesson connects a precise mathematical condition to a conclusion you can check. The transfer task asks you to change the setting and decide which parts of the reasoning still apply.

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Make a representation of your own.Sketch the quantities or relationships in this question before working through the solution. The cover image sets the learning scene; it does not show this problem’s exact values.

Set up the model

A useful answer starts with clear assumptions:

  • x is positive.
  • xˣ is interpreted through exp(x ln x).

02 · Work through the example

Follow the reasoning, one step at a time.

Try to predict the next step before reading it. After each calculation, explain why the operation makes sense and how it helps answer the original question.

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Work through it with Amar

See this example unfold.

The complete worked example, one idea at a time.

Text-led walkthrough · no audioAmar’s portrait was edited with AI.

Differentiate when the base and exponent both vary

Paused

Question: Start with the question. Paused.

Question

Start with the question

Differentiate y=xˣ for x>0.

Before you calculate

Read what is known and what you need to find. Make a prediction before moving to the first calculation.

Starts paused. Play advances through the full text at a reading pace; pause whenever you need more time. Previous, Next, and the phase buttons let you set your own pace. Playback pauses when this walkthrough leaves the screen or you switch tabs.

Your device’s reduced-motion setting keeps each phase still. Manual controls remain available. The full written solution stays below.

  1. Build the model

    ln y=x ln x

    Positivity permits taking a real logarithm.

  2. Work through the mathematics

    y′/y=ln x+1

    Differentiate the left by the chain rule and the right by the product rule.

  3. Check the conclusion

    y′=xˣ(ln x+1)

    Multiply by the original y to express the derivative in x.

The result

y′=xˣ(ln x+1)

Multiply by the original y to express the derivative in x.

Common mistakes to catch

  • The formula is not obtained by treating the exponent as fixed.
  • The stated real domain matters for taking logarithms.

03 · Practice independently

Try it before revealing the answer.

Use paper or a calculator as needed. Write your units and reasoning, then open the hint or explanation to check your approach.

Practice 1

Find y′ at x=1.

Show a hint

ln1=0 and 1¹=1.

Reveal answer and explanation

One

The product becomes 1·(0+1).

Practice 2

Why is the usual constant-exponent power rule insufficient?

Show a hint

The exponent also changes.

Reveal answer and explanation

It omits a contribution from the changing exponent

Logarithmic differentiation handles both sources of variation.

Take the idea with you

Identify which differentiation rule fits a variable appearing in both a base and its exponent.

04 · Reflect and continue

Can you explain it in your own words?

Before moving on, explain the main idea without looking at the worked example. Try both practice questions, check your reasoning, and name one mistake you now know how to avoid. Return to a step if you still need support.

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