Math With AmarA C A D E M Y

Grade 11 · Intermediate · 13 minute lesson

Reject a root introduced by squaring

Check transformed equation candidates in the original radical equation.

Lesson 7 of 30 in Grade 11. Take the time you need; the lesson estimate is a guide.

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01 · Read and understand

What you will learn

  • Check transformed equation candidates in the original radical equation.
  • Justify the conclusion "Only x=3 solves the original equation" using the stated assumptions.

Before you start

Square roots and quadratics.

Keep paper nearby. Read the question once for the context, then again to identify what is known and what you need to find.

Start with a question

Solve √(x+6)=x.

Why this math matters

Check transformed equation candidates in the original radical equation. This worked micro-lesson connects a precise mathematical condition to a conclusion you can check. The transfer task asks you to change the setting and decide which parts of the reasoning still apply.

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Make a representation of your own.Sketch the quantities or relationships in this question before working through the solution. The cover image sets the learning scene; it does not show this problem’s exact values.

Set up the model

A useful answer starts with clear assumptions:

  • All roots and unknowns are real.
  • √ denotes the nonnegative square root.

02 · Work through the example

Follow the reasoning, one step at a time.

Try to predict the next step before reading it. After each calculation, explain why the operation makes sense and how it helps answer the original question.

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Work through it with Amar

See this example unfold.

The complete worked example, one idea at a time.

Text-led walkthrough · no audioAmar’s portrait was edited with AI.

Reject a root introduced by squaring

Paused

Question: Start with the question. Paused.

Question

Start with the question

Solve √(x+6)=x.

Before you calculate

Read what is known and what you need to find. Make a prediction before moving to the first calculation.

Starts paused. Play advances through the full text at a reading pace; pause whenever you need more time. Previous, Next, and the phase buttons let you set your own pace. Playback pauses when this walkthrough leaves the screen or you switch tabs.

Your device’s reduced-motion setting keeps each phase still. Manual controls remain available. The full written solution stays below.

  1. Build the model

    The right side must be nonnegative, so x≥0

    A principal square root cannot equal a negative value.

  2. Work through the mathematics

    Squaring gives x+6=x², or (x−3)(x+2)=0

    The transformed equation has candidates three and minus two.

  3. Check the conclusion

    Only x=3 solves the original equation

    √9=3 works, while √4=2 is not −2.

The result

Only x=3 solves the original equation

√9=3 works, while √4=2 is not −2.

Common mistakes to catch

  • A valid squared equation is not always equivalent to the original.
  • Domain restrictions apply before algebraic manipulation.

03 · Practice independently

Try it before revealing the answer.

Use paper or a calculator as needed. Write your units and reasoning, then open the hint or explanation to check your approach.

Practice 1

Solve √(x+2)=−1 over R.

Show a hint

A principal square root is nonnegative.

Reveal answer and explanation

No solution

Squaring would hide the impossible sign condition.

Practice 2

Why must a squared solution be checked?

Show a hint

Squaring maps opposite signs to the same value.

Reveal answer and explanation

The transformed equation may be less restrictive

It can introduce candidates that fail the original equality.

Take the idea with you

Explain how a non-injective operation can create extra algebraic candidates.

04 · Reflect and continue

Can you explain it in your own words?

Before moving on, explain the main idea without looking at the worked example. Try both practice questions, check your reasoning, and name one mistake you now know how to avoid. Return to a step if you still need support.

Next lesson

Up next: Solve an absolute-value equation with a quadratic inside

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