Math With AmarA C A D E M Y

Intermediate · 9 minute lesson

Find every count that fits a package-mass range

Solve a double inequality and apply a whole-number restriction.

Lesson 18 of 30 in Algebra. Take the time you need; the lesson estimate is a guide.

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01 · Read and understand

What you will learn

  • Translate inclusive boundaries into symbols.
  • Apply operations to all parts of an inequality.
  • List the feasible integer counts.

Before you start

Solve linear inequalities with positive coefficients and interpret ≤.

Keep paper nearby. Read the question once for the context, then again to identify what is known and what you need to find.

Start with a question

An empty classroom package has mass 50 g. Each identical booklet adds 25 g. A fictional sorting rule accepts packages from 250 g through 350 g, inclusive. How many booklets are allowed?

Why this math matters

A permitted range has two boundaries, and a valid answer must respect both. A compound inequality keeps them together. The algebra describes an interval, while the physical objects limit the possible inputs to whole counts.

Make a representation of your own.Sketch the quantities or relationships in this question before working through the solution. The cover image sets the learning scene; it does not show this problem’s exact values.

Set up the model

A useful answer starts with clear assumptions:

  • Every booklet has exactly the stated mass in the model.
  • Only complete booklets are packed, and the fictional boundaries include both endpoints.

02 · Work through the example

Follow the reasoning, one step at a time.

Try to predict the next step before reading it. After each calculation, explain why the operation makes sense and how it helps answer the original question.

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The complete worked example, one idea at a time.

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Find every count that fits a package-mass range

Paused

Question: Start with the question. Paused.

Question

Start with the question

An empty classroom package has mass 50 g. Each identical booklet adds 25 g. A fictional sorting rule accepts packages from 250 g through 350 g, inclusive. How many booklets are allowed?

Before you calculate

Read what is known and what you need to find. Make a prediction before moving to the first calculation.

Starts paused. Play advances through the full text at a reading pace; pause whenever you need more time. Previous, Next, and the phase buttons let you set your own pace. Playback pauses when this walkthrough leaves the screen or you switch tabs.

Your device’s reduced-motion setting keeps each phase still. Manual controls remain available. The full written solution stays below.

  1. Model the allowed total

    250 ≤ 50 + 25n ≤ 350

    The package mass must be at least 250 g and at most 350 g. Both conditions apply to the same count n.

  2. Remove the empty package

    200 ≤ 25n ≤ 300

    Subtract fifty from all three parts. This expresses the allowed mass contributed by booklets alone.

  3. Convert mass to counts

    8 ≤ n ≤ 12; n ∈ {8, 9, 10, 11, 12}

    Divide all parts by positive twenty-five, so the inequality directions stay unchanged. Keep only whole counts in the resulting interval.

The result

The package may contain 8, 9, 10, 11, or 12 booklets.

The algebraic real-number interval is [8, 12], but 8.5 booklets is excluded by the context. Checking the boundary counts gives total masses of 250 g and 350 g exactly.

Common mistakes to catch

  • Forgetting the empty package allows too many booklets.
  • Treating 'through 350 inclusive' as 'less than 350' wrongly removes the upper endpoint.

03 · Practice independently

Try it before revealing the answer.

Use paper or a calculator as needed. Write your units and reasoning, then open the hint or explanation to check your approach.

Practice 1

An empty box is 100 g and each item is 40 g. Which whole counts give totals from 260 g through 340 g?

Show a hint

Subtract one hundred, then divide by forty.

Reveal answer and explanation

4, 5, or 6 items

260 ≤ 100 + 40n ≤ 340 becomes 160 ≤ 40n ≤ 240, so 4 ≤ n ≤ 6.

Practice 2

In the original booklet problem, change the upper rule to strictly less than 350 g. Which counts remain?

Show a hint

Only the upper boundary's inclusion changes.

Reveal answer and explanation

8, 9, 10, or 11 booklets

The new condition is 8 ≤ n < 12. Twelve gives exactly 350 g, which is now excluded.

Take the idea with you

Underline words such as 'at least', 'less than', and 'inclusive' before choosing inequality signs.

04 · Reflect and continue

Can you explain it in your own words?

Before moving on, explain the main idea without looking at the worked example. Try both practice questions, check your reasoning, and name one mistake you now know how to avoid. Return to a step if you still need support.

Next lesson

Up next: Run a temperature-conversion function forwards and backwards

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